The best way to create an Picture Host Filename Generator in Python

The problem

You’re growing a picture internet hosting web site.

You need to create a operate for producing random and distinctive picture filenames.

Create a operate for producing a random 6 character string that shall be used to entry the picture URL.

To verify the title shouldn’t be already in use, you might be given entry to a PhotoManager object.

You’ll be able to name it like so to verify the title is exclusive

# at this level, the web site has just one picture, hosted on the 'ABCDEF' url
photoManager.nameExists('ABCDEF'); # returns true
photoManager.nameExists('BBCDEF'); # returns false

Notice: We think about two names with the identical letters however totally different instances to be distinctive.

The answer in Python code

Choice 1:

import uuid
def generateName():
    return str(uuid.uuid4())[:6]

Choice 2:

from random import pattern
from string import ascii_letters

def generateName(size=6):
    whereas True:
        title = ''.be a part of(pattern(ascii_letters, size))
        if not photoManager.nameExists(title):
            return title

Choice 3:

generateName=lambda:str(__import__("time").time())[-6:]

Check instances to validate our resolution

for i in vary(10):
    title = generateName();

    take a look at.anticipate(isinstance(title, str), "Identify needs to be a string.");
    take a look at.anticipate(photoManager.nameWasUnique(title), "Identify needs to be distinctive.");
    take a look at.assert_equals(len(title), 6, "Identify needs to be 6 digits lengthy.");